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Rename files using a list #

C:\temp>dir /b
89-bar.htm
a.htm
foo42.htm

C:\temp>type ..\list.txt
foo42.htm  001.htm
89-bar.htm 002.htm
a.htm      003.htm

C:\temp>for /f "tokens=1,2 delims= " %a in (..\list.txt) do ren %a %b
C:\temp>ren foo42.htm 001.htm
C:\temp>ren 89-bar.htm 002.htm
C:\temp>ren a.htm 003.htm

C:\temp>dir /b
001.htm
002.htm
003.htm

• If you save the for loop as a batch file, be sure to use double percent signs (e.g., %%a instead of %a).
• In this example, filenames contained no spaces, so delims was set to space. This could be changed to comma, bar, etc.
• For a dry run, prepend echo to ren %a %b.
• Be sure list.txt has DOS/Windows line endings (CR+LF)
• See also:
  • Rename from list, list rename using Quick File Rename
  • Rename a list of file with names from another list
  • Rename Files From A List of Current and New File Names
  • One Line Batch Rename Files Using CSV Input File and awk

/windows | Sep 22, 2011

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